The orbital speed of an artificial satellite very close to the surface of the earth is V0. Then the orbital speed of another artificial satellite at a height equal to three times the radius of the earth is
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a
4 Vo
b
2 Vo
c
0.5 Vo
d
3 Vo
answer is C.
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Detailed Solution
v∝1r, If r=R then v=V0 If r=R+h=R+3R=4R then v=V02=0.5V0