Questions
The orbital speed of a satellite moving in circular orbit around the earth (Radius = R) is equal to 50% of the escape velocity on the surface of earth. Then height of the satellite above the surface of earth is
detailed solution
Correct option is C
V=50% of Ve∴ GMr=122GMR⇒r=2R∴ h=r−R=2R−R=RTalk to our academic expert!
Similar Questions
The masses, each of mass m are kept on the vertices of an equilateral triangle of side a. Find the work needed to be done to change the length of the triangle twice of its original value.
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