The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is v. For a satellite orbiting at an altitude of half of the earth's radius, the orbital velocity is
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a
32v
b
32v
c
23v
d
23v
answer is C.
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Detailed Solution
v=GMR+h For first satellite h=0,v1=GMR For second satellite h=R2,v2=2GM3Rv2=23v1=23v