First slide

Accuracy; precision of instruments and errors in measurements

Question

The order of $2^{30}$ is approximately

Moderate

A

$10^{9}$
B

$10^{5}$
C

$10^{15}$
D

$10^{20}$

Solution

${(2)}^{30} = 1073741824 = 10^{9}$

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