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In order to determine the e.m.f. of a storage battery it was connected in series with a standard cell (both are adding)  in a certain circuit and a current I1 was obtained. When polarity of the standard cell is reversed, a current I2. was obtained in the same direction as that of I1. What is the
e.m.f. ε1 of the storage battery? The e.m.f. of the standard cell is ε2

a
ε1 = I1 + I2I1 − I2  ε2
b
ε1 = I1 + I2I2 − I1  ε2
c
ε1 = I1 + I2I1 + I2  ε2
d
ε1 = I2 - I1I1 + I2  ε2

detailed solution

Correct option is A

ε1+ε2= I1R,  ε1−ε2=I2RDividing above two equations, ε1 = I1 + I2I1 − I2ε2

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