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Order of magnitude of density of uranium nucleus is $(m_{p} = 1.67 \times 10^{- 27} kg)$

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Correct option is B

The order of magnitude of mass and volume of uranium nucleus will be m≃A1.67×1027kg (A is atomic number)V=43πr3≃43π1.25×10−15mA1/33≃8.2×10−45m3AHence, ρ=mV=A(1.67×10-27kg)(8.2×10-45m3)A≃2.0×1017kg/m3

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Order of magnitude of density of uranium nucleus is (mp=1.67×10-27kg)

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Order of magnitude of density of uranium nucleus is $(m_{p} = 1.67 \times 10^{- 27} kg)$