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In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be (g = 10 ms-2 and radius of earth is 6400 kms) 

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By Expert Faculty of Sri Chaitanya
a
0  rad sec−1
b
1800rad sec−1
c
180rad sec−1
d
18rad sec−1

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detailed solution

Correct option is B

g'=g−ω2Rcos2λ For weightlessness at equator λ=0 and g'= 0∴0=g−ω2R⇒ω=gR=1800 rads
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If R is the radius of earth, ω is its angular velocity and gp is the value of acceleration due to gravity at the poles, then effective value of acceleration due to gravity at the latitude λ=60 will be equal to

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