First slide

Application of Newtons laws

Question

In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration 5g/4 relative to the rope. The tension in the rope is (take g=10 ms^-2)

Moderate

A

$\frac{4875}{8} N$
B

$\frac{4875}{2} N$
C

$\frac{4875}{4} N$
D

$\frac{4875}{6} N$

Solution

Let T be the tension in the rope and a the acceleration of rope.
The absolute acceleration of man is, therefore $(\frac{5 g}{4} - a) .$
Equations of motion for mass and man gives:
$\begin{array}{l} T - 100 g = 100 a . . . . . (i) \\ T - 60 g = 60 (\frac{5 g}{4} - a) . . . . . (i i) \end{array}$
Solving Eqs (i) and (ii), we get $T = \frac{4875}{4} N$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App