Questions
In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration 5g/4 relative to the rope. The tension in the rope is (take g=10 ms-2)
detailed solution
Correct option is C
Let T be the tension in the rope and a the acceleration of rope.The absolute acceleration of man is, therefore 5g4−a.Equations of motion for mass and man gives:T−100g=100a .....(i)T−60g=605g4−a .....(ii)Solving Eqs (i) and (ii), we get T=48754NTalk to our academic expert!
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Figure shows block A a motor C mounted on a with combined mass m and another block B of mass 2m. Block B is attached to shaft of motor with a light inextensible string. Motor is switched on at t =0 and string starts winding on its shaft and block B starts moving at acceleration a. If initial separation between blocks is l then find the time after which the two bodies will collide. The friction coefficient between blocks and ground is .
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