In order to raise a mass of $$100$$ kg a man of mass $$60$$ kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration $$5g/4$$ relative to rope. The tension in the rope is (g$$ $$=$$ $$10$$ $$m/s2).

Question

Infinity Learn · Accepted Answer

For man T–mg $$=$$ $$m(a$$–$$a1)For$$ load T–Mg $$=$$ $$Ma1Mg-mg=ma-m+Ma1Solving$$ $$a1$$ $$=$$ $$2.19$$ $$m/s2T$$–$$100g$$ $$=$$ $$100(2.19)$$ ; T $$=$$ $$1219$$ NHere a $$=$$ Acceleration of the man relative to the rope and $$a1$$ is the acceleration of the $$100$$ kg mass i.e., acceleration of the rope. So acceleration of the man relative to the ground $$=$$ (a-a1).

Different types of Forces

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In order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration 5g/4 relative to rope. The tension in the rope is (g = 10 m/s²).

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Different types of Forces

Remember concepts with our Masterclasses.

In order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration 5g/4 relative to rope. The tension in the rope is (g = 10 m/s2).

Ready to Test Your Skills?

free study material

In order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration 5g/4 relative to rope. The tension in the rope is (g = 10 m/s²).