Questions
An organ pipe is closed at one end has fundamental frequency of 1500 Hz. The maximum number of overtones generated by this pipe which a normal person can hear is :
detailed solution
Correct option is C
Critical hearing frequency for a person is 20,000Hz. If a closed pipe vibration in Nth mode then frequency of vibration n=(2N−1)v4l=(2N−1)n1(where n1 = fundamental frequency of vibration)Hence 20,000 =(2N−1)×1500⇒N=7.1≈7Also, in closed pipe Number of over tones = (No. of mode of vibration) –1 = 7 – 1 = 6.Talk to our academic expert!
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A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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