An organ pipe is closed at one end has fundamental frequency of 1500 Hz. The maximum number of overtones generated by this pipe which a normal person can hear is:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
14
b
13
c
6
d
9
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Critical hearing frequency for a person is 20,000 Hz. If a closed pipe vibration in Nth mode then frequency of vibration n=(2N−1)v4l=(2N−1)n1 (where n1 fundamental frequency of vibration) Hence 20,000=(2N−1)×1500⇒N=7.1≈7Also, in closed pipeNumber of over tones =( No. of mode of vibration )−1 =7−1=6