First slide

Standing waves

Question

An organ pipe of effective length 0 . 6 m is closed at one end. Given that the speed of the sound in air is 300 m/sec, the two lowest frequencies for the pipe are

Easy

A

25OHz,75OHz
B

250 Hz, 5O0 Hz
C

125Hz, 375 Hz
D

125Hz,250Hz

Solution

$n = (2 r + 1) \frac{V}{2 l} where r = 0, 1, 2, â¦ n_{1} = \frac{V}{4 l} = \frac{300}{4 Ã 0 â 6} = 125 Hz n_{2} = \frac{3 V}{4 l} = 3 n_{1} = 375 Hz$

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