Questions
An organ pipe, open from both ends produces 5 beats per second when vibrated with a source of frequency 200 Hz. The second harmonic of the same pipes produces 10 beats per second with a source of frequency 420 Hz. The frequency of source is
detailed solution
Correct option is B
Initially number of beats per second = 5∴ Frequency of pipe = 200 ± 5 = 195 Hz or 205 Hz ...(i) Frequency of second harmonics of the pipe = 2n and number of beats in this case = 10∴ 2n = 420 ± 10 ⇒ 410 Hz or 430 Hz ⇒ n = 205 Hz or 215 Hz ... (ii) From equation (i) and (ii) it is clear that n = 205 HzTalk to our academic expert!
Similar Questions
A metal wire of diameter 1.5 mm is held on two knife edges separated by a distance 50 cm the tension in the wire is 100 N the wire vibrating with its fundamental frequency and vibrating tuning fork together produces 5 beats per second. The tension in the wire is then reduced to 81 N, when the two are excited, beats are heard at the same rate. Calculate frequency of the fork.
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