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Q.

The oscillating electric field of an electromagnetic wave is given by  EY=30sin[2×1011t+300πx]Vm−1. Then , the value of wavelength of the electromagnetic wave is

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a

1150m

b

1100m

c

150m

d

1250m

answer is A.

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Detailed Solution

Given equation is  EY=30sin[2×1011t+300πx]Vm−1Comparing the given equation with the equation of  EY=E0sin[2πtT+2πxλ]  we get,     2πλ=300π ⇒1λ=150 ⇒λ=1150m
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