First slide

Introduction-Electromagnetic waves

Question

The oscillating electric field of an electromagnetic wave is given by $E_{Y} = 30 \sin [2 \times 10^{11} t + 300 π x] V m^{- 1}$ . Then , the value of wavelength of the electromagnetic wave is

Easy

A

$\frac{1}{150} m$
B

$\frac{1}{100} m$
C

$\frac{1}{50} m$
D

$\frac{1}{250} m$

Solution

Given equation is $E_{Y} = 30 \sin [2 \times 10^{11} t + 300 π x] V m^{- 1}$
Comparing the given equation with the equation of $E_{Y} = E_{0} \sin [\frac{2 π t}{T} + \frac{2 π x}{λ}]$ we get,
$\frac{2 π}{λ} = 300 π \Rightarrow \frac{1}{λ} = 150 \Rightarrow λ = \frac{1}{150} m$

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