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Q.

In outer space where gravity is zero, acceleration of a rocket of mass 100 kg is 12 m/s2. If velocity of exhaust gases relative to the rocket is 300 m/s, then rate of consumption of fuel is

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answer is 4.

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Detailed Solution

T = Thrust generated = 100 x 12 N = 1200 NNow, Vrdmdt=T⇒dmdt=TVr=1200300 kg/s=4 kg/s
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