P and Q are two points at distances 10 cm and 20 cm from the axis of a long thin straight current carrying wire. Then the ratio of magnetic energy densities at P and Q is
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a
2 : 1
b
4 : 1
c
8 : 1
d
16 : 1
answer is B.
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Detailed Solution
(2)At distance r from the axis of a current carrying wire,B=μ0i2πr and magneticenergy density u=B22μ0 = μ0i28π2.r2 ⇒ u ∝ 1r2∴ uPuQ= 20102=4