First slide

Vectors

Question

P, Q and R are three coplanar forces acting at a point and are in equilibrium. Given P = 1.9318 kg-wt, sin $θ_{1} = 0.9659, the value of R is (in kg - wt)$

Moderate

A

0.9659
B

2
C

1
D

$\frac{1}{2}$

Solution

$\frac{P}{\sin θ_{1}} = \frac{Q}{{sinθ}_{2}} = \frac{R}{\sin 150^{0}}$
$\Rightarrow \frac{1.93}{\sin θ_{1}} = \frac{R}{\sin 150^{0}}$
$\Rightarrow R = \frac{1.93 \times \sin 150^{0}}{\sin θ_{1}} = \frac{1.93 \times 0.5}{0.9659} = 1$

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