P – T curve of a cyclic process is shown. If number of moles of the gas are n, the work done by the gas in the given process is

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nRT1+T3−T4+T2

nRT1−T3−T4+T2

nRT1+T3+T4−T2

nRT1+T3−T4−T2

answer is D.

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Detailed Solution

Work done along AB and CD is zero. Paths BC and DA are isobaric.Hence W=WBC+WPAW=nRT1+T3−T4−T2

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