The pair of quantities having same dimensions is

detailed solution

Correct option is C

Impulse = Force × time = [MLT -2][T] = [MLT-1]Surface tension =  Force  length =MLT−2[L]=ML0T−2Angular momentum= Moment of inertia × angular velocity= [ML2][T-1] = [ML2T-1]Work = Force × distance = [MLT-2][L] = [ML2T-2]Energy = [ML2T-2] Torque = Force × distance = [MLT-2][L] = [ML2T-2]  Young’s modulus= Force / Area  Change in length / original length =MLT−2/L2[L]/[L]=ML−1T−2Hence, among the given pair of physical quantities work and torque have the same dimensions [ML2T-2].