The pair of quantities having same dimensions is

detailed solution

Correct option is C

Impulse = Force × time  =MLT-2[T]=MLT-1  Surface tension = Force  length  =MLT-2[L]=ML0 T-2  Angular momentum   = Moment of inertia × angular velocity  =ML2T-1=ML2 T-1  Work = Force × distance  =MLT-2[L]=ML2 T-2  Energy =ML2 T-2  Torque = Force × distance  =MLT-2[L]=ML2 T-2  Young's modulus  = Force / Area  Change in length / original length  =MLT-2/L2[L]/[L]=ML-1 T-2  Hence, among the given pair of physical quantities work and torque have the same dimensions ML2 T-2.