A parabolic section of wire OA is located in the x-y plane and carries current I = 12 A. A uniform magnetic field B = 4.0 T making an angle 600 with x axis exists in x-y plane. Calculate the magnetic force on the wire OA. Coordinates of A are (0.25 m, 1 m).
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a
63 −4k k^N
b
64-3 k^ N
c
33 −4k^ N
d
34-3 k^ N
answer is A.
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Detailed Solution
Magnetic field is uniform, apply F→=lL→ × B→ where L→ = 0.25 i^+j^ and B→ = 4cos 60i^+sin60j^ =2i^+23j^ Therefore F→=6(3 -4)k^ N