A parabolic section of wire OA is located in the x-y plane and carries current I = 12 A. A uniform magnetic field B=4.0T making an angle 600 with x axis exists in x-y plane.Calculate the magnetic force on the wire OA. Co-ordinates of A are (0.25 m, 1 m).

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6(3-4)k^ N

6(4-3)k^ N

3(3-4)k^ N

3(4-3)k^ N

answer is A.

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Detailed Solution

Magnetic field is uniform, apply F→=iL→×B→ where L→=0.25i^+j^ and B→=4(cos60i^+sin60j^ ) F=120.25i^+j^ × 4(cos60i^+sin60j^ ) =6(3-4)k^ N

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