A parachutist after bailing out fall for $$5$$ $$sec$$ and when it open he descends with an deceleration of $$1$$ $$m/s2$$ and reach the ground with a speed of $$3$$ $$m/s$$ .Find the height at which he was dropped.

Question

A parachutist after bailing  out fall for $$5$$ $$sec$$ and when it open he descends with an deceleration of $$1$$ $$m/s2$$ and reach the ground with a speed of $$3$$ $$m/s$$ .Find the height at which he was dropped.

Infinity Learn · Accepted Answer

till up to $$5$$ $$sec$$  he is like a freely falling bodywe know, $$S=Ut+12at2$$, here $$displacement=S$$;initial $$velocity=U$$; $$time=t$$; $$acceleration=a$$; up to $$5$$ $$sec$$ it is like a freely falling body     $$S=0+12g52$$ $$S=12$$×$$10$$×$$5$$×$$5=125m$$ The velocity parachutist  gain  at $$t=5sec$$ $$V=U+at$$   ⇒$$V=0+10$$×$$5$$ ⇒$$V=50m/sAfter$$ the parachute is open initial velocity $$U=50m/s$$;final velocity   $$V=3m/s$$; acceleration     $$a=$$−$$1m/s2$$ ; $$displacement=$$  $$S=$$?  we know,$$V2$$−$$U2=2as$$ substitute the values in above $$equation32$$−$$502=2$$−$$1S$$ ⇒$$S=1245.5m$$ Total height is $$1245.5+125=1370.5m$$

A parachutist after bailing out fall for 5 sec and when it open he descends with an deceleration of $1 m / s^{2}$ and reach the ground with a speed of $3 m / s$ .Find the height at which he was dropped.

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A parachutist after bailing out fall for 5 sec and when it open he descends with an deceleration of 1 m/s2 and reach the ground with a speed of 3 m/s .Find the height at which he was dropped.

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A parachutist after bailing out fall for 5 sec and when it open he descends with an deceleration of $1 m / s^{2}$ and reach the ground with a speed of $3 m / s$ .Find the height at which he was dropped.