A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3 m/s. At what height, did he bail out ?

The velocity when the parachutist falls through a distance 50 m is given byv2 =(0)2 +2 x 9.8 x 50 = 980Now, this becomes the initial velocity for the next journey. when he reaches the ground his velocity v = 3 m.s. Therefore,(3)2 = v2 - 2 f hor (3)2 =980 -2x2xhh - 242.75Total height = 50 + 242 .75= 292.75 = 293 m