First slide
Release from certain height
Question

A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3m/s. at what height, did he bail out?

Easy
Solution

velocity reached after travelling for 50 m, v2= 2g×50 v= 980 Also, 32= 980-2×2×s s= 971/4= 243 m Hence total height= 243+50= 293 m  

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