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Q.

A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3m/s. At what height, did he bail out?

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a

91 m

b

182 m

c

293 m

d

111m

answer is C.

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Detailed Solution

Speed when parachute opens:  v2= 2(9.8)50 v= 980 height covered with parachute: 32=980- 2×2×s 4s= 971 s= 242.75 m hence height at which he bails out= 242.75+ 50= 293 m
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