A parachutist after bailing out falls $$50m$$ without friction. When parachute opens, it decelerates at $$2$$ $$m/s2$$. He reaches the ground with a speed of $$3$$ $$m/s$$. At what height from ground did he bail out?

Question

A parachutist after bailing out falls $$50m$$ without friction. When parachute opens, it decelerates at $$2$$ $$m/s2$$. He reaches the ground with a speed of $$3$$ $$m/s$$. At what height from ground did he bail out?

Infinity Learn · Accepted Answer

given initial velocity of $$parachutist=u=0$$; $$distance=s=50m$$;acceleration due to $$gravity=g=9.8m/s2substitute$$ given values in,       $$v2$$−$$u2=2as$$     $$v2=2$$×$$9.8$$×$$50$$    $$v2=980$$ $$m/s---(1)v=The$$ velocity after he descends $$50m$$ after $$50m$$ parachute opens;  final velocity $$=v=3m/s$$; $$a=-2m/s2$$ initial velocity $$=u$$⇒$$u2=980$$ substitute, to obtain distance,  in $$v2$$−$$u2=2as$$ $$32-980=2(-2)s$$ $$s=9724=243m$$ The height at which he bailed out $$=h=243+50=293m$$

A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at $2 m / s^{2}$ . He reaches the ground with a speed of 3 m/s. At what height from ground did he bail out?

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A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3 m/s. At what height from ground did he bail out?

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A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at $2 m / s^{2}$ . He reaches the ground with a speed of 3 m/s. At what height from ground did he bail out?