A parachutist bailing out fall for $$5$$ $$sec$$ and when it open it descends with an deceleration of $$1$$ $$m/s2$$ and reach the ground with a speed of $$3$$ $$m/s$$ find the height at which he was dropped.

Question

A parachutist bailing out fall for $$5$$ $$sec$$ and when it open it descends with an deceleration of $$1$$ $$m/s2$$ and reach the ground with a speed of $$3$$ $$m/s$$ find the height at which he was dropped.

Infinity Learn · Accepted Answer

till up to $$5$$ $$sec$$ it is like a freely falling $$bodyS=Ut+12at2$$,$$S=0+12(g)52$$ $$S=12$$×$$10$$×$$5$$×$$5=125mThe$$ velocity it gain $$V=U+at$$  ⇒$$V=0+10$$×$$5$$⇒$$V=50m/sAfter$$ the parachute is $$openU=50m/s$$   $$V=3m/s$$    $$a=$$−$$1m/s2$$   $$S=$$? From $$V2$$−$$U2=2s32$$−$$502=2$$−$$1S$$⇒$$S=1245.5m$$ Total height is $$1245.5+125=1370.5m$$

A parachutist bailing out fall for 5 sec and when it open it descends with an deceleration of $1 m / s^{2}$ and reach the ground with a speed of 3 m/s find the height at which he was dropped.

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A parachutist bailing out fall for 5 sec and when it open it descends with an deceleration of 1 m/s2 and reach the ground with a speed of 3 m/s find the height at which he was dropped.

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Ready to Test Your Skills?

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A parachutist bailing out fall for 5 sec and when it open it descends with an deceleration of $1 m / s^{2}$ and reach the ground with a speed of 3 m/s find the height at which he was dropped.