A parachutist drops first freely from an aeroplane for $$10$$ s and then his parachute opens out. Now he descends with a net retardation of $$2.5$$ $$ms-2$$. If he bails out of the plane at a height of $$2495$$ m and g $$=$$ $$10$$ $$ms-2$$, his velocity on reaching the ground will be

Question

A parachutist drops first freely from an aeroplane for $$10$$ s and then his parachute opens out. Now he descends with a net retardation of $$2.5$$ $$ms-2$$. If he bails out of the plane at a height of $$2495$$ m and g $$=$$ $$10$$ $$ms-2$$, his velocity on reaching the ground will be

Infinity Learn · Accepted Answer

The velocity v acquired by the parachutist after $$10$$ s:v $$=$$ u $$+$$ gt $$=$$ $$0$$ $$+$$ $$10$$ × $$10$$ $$=$$ $$100$$ $$ms-1Then$$,  $$s1=ut+12gt2=0+12$$ × $$10$$ × $$102$$ $$=$$ $$500mThe$$ distance travelled by the parachutist under retardation $$iss2=$$ $$2495$$ $$-$$ $$500$$ $$=$$ $$1995$$ m Let vg be the velocity on reaching the ground. $$Thenvg2$$ $$-v2=$$ $$2as2$$ or $$vg2-(100)2$$ $$=$$ $$2$$ × $$(-2.5)$$ × $$1995$$  or $$vg=5$$ $$ms-1$$

A parachutist drops first freely from an aeroplane for 10 s and then his parachute opens out. Now he descends with a net retardation of $2.5 {ms}^{- 2}$ . If he bails out of the plane at a height of 2495 m and $g = 10 {ms}^{- 2}$ , his velocity on reaching the ground will be

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A parachutist drops first freely from an aeroplane for 10 s and then his parachute opens out. Now he descends with a net retardation of 2.5 ms-2. If he bails out of the plane at a height of 2495 m and g = 10 ms-2, his velocity on reaching the ground will be

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A parachutist drops first freely from an aeroplane for 10 s and then his parachute opens out. Now he descends with a net retardation of $2.5 {ms}^{- 2}$ . If he bails out of the plane at a height of 2495 m and $g = 10 {ms}^{- 2}$ , his velocity on reaching the ground will be