Q.
PARAGRAPH A tool moving in x-y plane under a quality control process under the action of various forces. One force is F→=− α x y2j^ , a force in the negative y-direction whose magnitude depends on the position of the tool. The constant α is 2.50 N/m3. Consider the displacement of the tool from the origin to the point x = 3.00 m, y = 3.00 m.Q. Calculate the work done on the tool by the force F→ if this displacement is along the straight line y = x that connects these two points
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a
– 50.6 joule
b
– 67.5 joule
c
– 77.5 joule
d
– 60.5 joule
answer is A.
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Detailed Solution
w=∫F→ (dxi^+dyj^) w=−∫03α y3dy (∴ x = y) = −2.5(y44)03=−2.54.(81) w=−50.6 J
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