Download the app

Questions  

PARAGRAPH

A tool moving in x-y plane under a quality control process under the action of various forces.  One force is F=αxy2j^ , a force in the negative y-direction whose magnitude depends on the position of the tool.  The constant α  is 2.50 N/m3.  Consider the displacement of the tool from the origin to the point  x = 3.00 m, y = 3.00 m.

Q. Calculate the work done on the tool by the force F  if this displacement is along the straight line y = x that connects these two points

a
– 50.6 joule
b
– 67.5 joule
c
– 77.5 joule
d
– 60.5 joule

detailed solution

Correct option is A

w=∫F→ (dxi^+dyj^)      w=−∫03α y3dy                              (∴  x = y)      = −2.5(y44)03=−2.54.(81)               w=−50.6 J

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A force F=K(yi+xj)  (where K is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force F on the particles is


phone icon
whats app icon