A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is

Question

A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is

Infinity Learn · Accepted Answer

For the second minimum, Path difference $$2$$λ Therefore, corresponding value of phase difference is Δϕ$$=2$$πλ× Path difference  ∴  Δϕ$$=2$$πλ×$$2$$λ$$=4$$π

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material