First slide

Diffraction

Question

A parallel beam of monochromatic light of wavelength 5000 $Å$ is incident normally on a single narrow slit of width 0.001 mm. the light is focused by convex lens on a screen placed on focal plane. The first minimum will be formed for the angle of diffraction equals to

Easy

A

0^o
B

15^o
C

30^o
D

50^o

Solution

$For a narrow slit, esin θ = nλ \sin θ = \frac{λ}{d} (∵ n = 1) or \sin θ = \frac{5000 \times 10^{- 10}}{0 .001 \times 10^{- 3}} = 0 .5 θ = \sin^{- 1} (0 \cdot 5) = \sin^{- 1} (1 / 2) = 30^{\circ}$

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