A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by ${\mathrm{Q}}_0,{\mathrm{V}}_0,{\mathrm{E}}_0$ and U₀ respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities now given by Q,V,E and U are related to the previous quantities as :

• A

  $\mathrm{Q}>{\mathrm{Q}}_0$

• B

  $\mathrm{V}>{\mathrm{V}}_0$

• C

  $\mathrm{E}>{\mathrm{E}}_0$

• D

  $\mathrm{U}<{\mathrm{U}}_0$