A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by $$Q0$$,$$V0$$,$$E0$$ and $$U0$$ respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities now given by Q,V,E and U are related to the previous quantities as :

Question

A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by $$Q0$$,$$V0$$,$$E0$$ and $$U0$$ respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities now given by Q,V,E and U are related to the previous quantities as :

Infinity Learn · Accepted Answer

∵$$Q=CVWith$$ the introduction of dielectric slab, C increases but V remains unchanged because battery is connected.∴Charge (Q) increases due to increase in C,∴Q>$$Q0Also$$,     $$U=12CV2$$∵C>$$C0$$,$$V=V0Then$$, U>$$U0$$

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