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Q.

A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by Q0,V0,E0 and U0 respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities now given by Q,V,E and U are related to the previous quantities as :

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a

Q>Q0

b

V>V0

c

E>E0

d

U

answer is A.

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Detailed Solution

∵Q=CVWith the introduction of dielectric slab, C increases but V remains unchanged because battery is connected.∴Charge (Q) increases due to increase in C,∴Q>Q0Also,     U=12CV2∵C>C0,V=V0Then, U>U0
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