A parallel plate air capacitor has a capacitance of 50μF . The plates are at a distance d apart. If a slab of thickness t(t≤d) and dielectric constant 4 is introduced between the parallel plates, then the capacitance will be

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50 μF

100 μF

200 μF

500 μF

answer is B.

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Detailed Solution

Capacitance will increase but not 4 times (because dielectric is not filled completely). Hence new capacitance may be 100 μF.

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