A parallel plate air capacitor has capacity C, distance of separation between plates is d and potential difference V is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is

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CV2d

C2V22d2

C2V22d

CV22d

answer is D.

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Detailed Solution

Force of attraction between the plates of the parallel plate air capacitor isF=Q22ε0Awhere Q is the charge on the capacitor, ε0 is the permittivity of free space and A is the area of each plate. But Q=CV and C=ε0Ad or ε0A=Cd ∴ F=C2V22Cd=CV22d

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