A parallel plate capacitor of capacitance C is connected to a battery and is charged to a potential V0. Another capacitor of capacitance 2C is charged to a potential of 2V0. Now both capacitors are connected to each other in such a way that positive plate of one is connected to negative plate of the other. The final potential difference across the combination is
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a
V0
b
3V02
c
2V03
d
4V03
answer is A.
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Detailed Solution
Net charge stored in the combination is given by Q=2C×2V0-CV0=3CV0Capacitance of the combination, C=C0+2C0=3C0∴ Final potential difference V=QC=3CV03C0=V0