A parallel plate capacitor of capacitance C is connected to a battery and is charged to a potential $$V0$$. Another capacitor of capacitance $$2C$$ is charged to a potential of $$2V0$$. Now both capacitors are connected to each other in such a way that positive plate of one is connected to negative plate of the other. The final potential difference across the combination is

Question

Infinity Learn · Accepted Answer

Net charge stored in the combination is given by $$Q=2C$$×$$2V0-CV0=3CV0Capacitance$$ of the combination, $$C=C0+2C0=3C0$$∴ Final potential difference $$V=QC=3CV03C0=V0$$

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