A parallel plate capacitor of capacitance C (without dielectrics) is filled by dielectric slabs as shown in figure. Then the new capacitance of thecapacitor is

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3.9 C

4 C

2 C

3 C

answer is A.

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Detailed Solution

C=∈0WdC1=6∈0Wd; C2=4∈0WdC3=6∈0Wd; C4=2∈0WdCeq=C1C2C1+C2+C3C4C3+C4

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