Q.

A parallel plate capacitor of capacitance 20μF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively

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a

zero, zero

b

zero, 60μA

c

60μA,60μA

d

60μA, zero

answer is C.

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Detailed Solution

Here, C=20μF  Therateofchangeofpotential =3 V/s  Thechargeonthecapacitor, Q=CV ∴ dQdt=ID=CdVdt=20μF×3 V s=60μA  Displacementcurrentisequaltotheconductioncurrent.
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