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A parallel plate capacitor of capacity 100pF is connected to 230V of AC supply of 300rad/s frequency. The value of displacement current is

a
6.9μA
b
2.3μA
c
9.2μA
d
4.6μA

detailed solution

Correct option is A

Displacement current, ID=VZ=VXC  where Z is independence and XC is  capacitive reactance XC=1ωc                   ⇒ ID=V1/ωc=V×ωc ⇒ID=230×300×100×10−12 ⇒ID=69×10−7=6.9μA

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