Q.

A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increased.

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a

The force of attraction between the plates will decrease.

b

The field in the region between the plates will not change.

c

The energy stored in the capacitor will increase.

d

The potential difference between the plates will decrease.

answer is B.

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Detailed Solution

C=QV  Also, C=ε0AdAs d increases, C will decrease. Therefore, V should increase, as Q remains the same.E=Vd=QAε0 will be constant.Energy, U=Q22C. As C decreases, U will increase.
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