A parallel plate capacitor (condenser) has a certain capacitance (capacity). When 2/3 rd of the distance between the plates is filled with a dielectric, the (capacity) capacitance is found to be 2.25 times the initial capacitance. The dielectric constant of the dielectric

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answer is D.

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Detailed Solution

C = 2.25C0⇒2.25Aε0d=Aε0d-23d1-1K=Aε0d-2d3+2d3K 1d3+2d3K=2.25d=3Kd(K+2)⇒2.25K + 4.5 = 3K ⇒ 0.75K = 4.5K=4.50.75=45075=6

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