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Q.

A parallel plate capacitor consists of two circular plates each of plate area 8cm2 and separated by 4.0mm.    The capacitor is being charged by an external source. The charging current is constant and is equal to 8.85mA. The rate of change of potential difference b/w the plates will be

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a

5×109V/s

b

5×1010V/s

c

5×108V/s

d

5×107V/s

answer is A.

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Detailed Solution

id=CdVdt Here C = capacitance of parallel plate capacitor           id = Displacement current                dVdt= Rate of change of potential difference  ⇒dVdt=idC=id×d∈0A=8.85×10−3×4×10−38.85×10−12×8×10−4=5×109V/s
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A parallel plate capacitor consists of two circular plates each of plate area 8cm2 and separated by 4.0mm.    The capacitor is being charged by an external source. The charging current is constant and is equal to 8.85mA. The rate of change of potential difference b/w the plates will be