Questions
A parallel plate capacitor consists of two circular plates each of plate area and separated by The capacitor is being charged by an external source. The charging current is constant and is equal to The rate of change of potential difference b/w the plates will be
detailed solution
Correct option is A
id=CdVdt Here C = capacitance of parallel plate capacitor id = Displacement current dVdt= Rate of change of potential difference ⇒dVdt=idC=id×d∈0A=8.85×10−3×4×10−38.85×10−12×8×10−4=5×109V/sTalk to our academic expert!
Similar Questions
A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400 V. if the plate area is 60 , then the value of displacement current for will be
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