Q.
A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is
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a
Charge Q
b
Potential V
c
Capacity C
d
Energy U
answer is A.
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Detailed Solution
When dielectric slab is introduced between the plates of a capacitor charge Q on the plates remains constant as it is not in connection with the charging battery.
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