Q.

A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

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a

Charge Q

b

Potential V

c

Capacity C

d

Energy U

answer is A.

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Detailed Solution

When dielectric slab is introduced between the plates of a capacitor charge Q on the plates remains constant as it is not in connection with the charging battery.
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