A parallel plate capacitor has a capacity C. The separation between the plates is doubled and a dielectric medium is introduced between the plates. If the capacity now becomes 2C, the dielectric constant of the medium is
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a
2
b
1
c
4
d
8
answer is C.
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Detailed Solution
C1=ε0Ad1 and C2=Kε0Ad2∴C1C2=1K×d2d1=C2C=1K×2dd⇒K=4