A parallel plate capacitor has plate area of $1c{m}^2$ and plate separation 0.5 mm. When the capacitor is being charged, the electric field in the space between the plates is increasing at the rate of ${10}^{10}\mathrm{V}/\mathrm{m}-\mathrm{s}$. Then the displacement current at that instant is 

• A

  4.85 $\mathrm{\mu A}$

• B

  12.15 $\mathrm{\mu A}$

• C

  6.25 $\mathrm{\mu A}$

• D

  8.85 $\mathrm{\mu A}$