A parallel plate capacitor has plate area A and separation d. It is charged to a potential difference V0. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is
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a
3ε0AV02d
b
ε0AV022d
c
ε0AV023d
d
ε0AV02d
answer is D.
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Detailed Solution
Work done W=Uf−UiUi=12CV02 and Uf=12(C)3.(3V0)2=3×12CV02So W=ε0AV02d