Questions
A parallel plate capacitor has plates of area A separated by distance ‘d’ between them. It is filled with a dielectric which has a dielectric constant that varies as where ‘x’ is the distance measured from one of the plates. If , the total capacitance of the system is best given by the expression
detailed solution
Correct option is D
Capacitance of “dx” element C'=Kε0Adx Capacitance of “dx” element C'=K01+αxε0AdxAll such elements are connected in series. Hence, net capacitance is given by, ∑1C'=∫0ddxK0ε0A1+αx ⇒1C=1K0ε0Aαln1+αx0b∵∫1axdx=logaxa+c ⇒1C=1K0ε0Aαln1+αd Given αd<<1 ⇒1C=1K0ε0Aααd−α2d22 [using ln(1+x) = x-x22+...]⇒1C=dK0ε0A1−αd2 ⇒C=K0ε0Ad1-αd2-1 ⇒C=K0ε0Ad1+αd2 [using (1+x)n = 1+nx ]Talk to our academic expert!
Similar Questions
There is an air filled 1 pF parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to 2 pF. The dielectric constant of wax is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests