A parallel plate capacitor has plates of area A separated by distance ‘d’ between them. It is filled with a dielectric which has a dielectric constant that varies as kx=K01+αx where ‘x’ is the distance measured from one of the plates. If αd<<1, the total capacitance of the system is best given by the expression
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a
A∈0K0d1+αd22
b
A∈0K0d1+α2d22
c
AK0∈0d1+αd
d
AK0∈0d1+αd2
answer is D.
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Detailed Solution
Capacitance of “dx” element C'=Kε0Adx Capacitance of “dx” element C'=K01+αxε0AdxAll such elements are connected in series. Hence, net capacitance is given by, ∑1C'=∫0ddxK0ε0A1+αx ⇒1C=1K0ε0Aαln1+αx0b∵∫1axdx=logaxa+c ⇒1C=1K0ε0Aαln1+αd Given αd<<1 ⇒1C=1K0ε0Aααd−α2d22 [using ln(1+x) = x-x22+...]⇒1C=dK0ε0A1−αd2 ⇒C=K0ε0Ad1-αd2-1 ⇒C=K0ε0Ad1+αd2 [using (1+x)n = 1+nx ]