Questions
A parallel plate capacitor having cross-sectional area A and separation d has air in between the plates. Now an insulating slab of same area but thickness d/2 is inserted between the plates as shown in figure having dielectric constant K(= 4). The ratio of new capacitance to its original capacitance will be,
detailed solution
Correct option is C
C0=ε0AdAfter inserting dielectricC=ε0A(d−t)+tk=ε0Ad2+d8=8ε0A5d=85C0 So, CC0=85Talk to our academic expert!
Similar Questions
A parallel plate, air filled capacitor has capacitance C. When a dielectric material of dielectric constant 4 is filled so that half of the space between plates is occupied by it, then percentage increase in the capacitance is equal to
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