Questions
A parallel plate capacitor having plate area ‘A’ and plate separation ‘d’ is joined to a battery of emf ‘V’ and internal resistance ‘R’ at t=0 . Consider a plane surface of area parallel to the plates and situated symmetrically between them. Find the displacement current through this surface as a function of time. [ The charge on the capacitor at time ‘t’ is given by ]
detailed solution
Correct option is B
Surface charge density, σ=qA=CVA1−e−tτ Electric field b/w the plates of capacitor, E=σ∈0=CV∈0A1−e−tτ Electric flux from the given area, ϕE=EA3=CV3∈01−e−tτ Displacement current, id=∈0dϕEdt=∈0ddtCV3∈01−e−tτ=CV3τe−tτ ⇒id=V3Re−tCR ⇒id=V3Re−td∈0ARTalk to our academic expert!
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A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400 V. if the plate area is 60 , then the value of displacement current for will be
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