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Q.

A parallel plate capacitor having plates of area  S and plate separation  d, has capacitance C1  in air.  When two dielectrics of different relative permittivities  ε1=2 and ε2=4 are introduced between the two plates as shown in the figure, the capacitance becomes  C2.  The ratio C2C1  is

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a

6/5

b

5/3

c

7/5

d

7/3

answer is D.

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Detailed Solution

C1=ε0Ad (in air) Capacitance of Lower part =2ε0A/2d=C1 Capacitance of Top Left part =2ε0A/2d/2=2C1 Capacitance of Top Right part =4ε0A/2d/2=4C1C2=2C1S4C1PC1=86C1+C1=73C1
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